Q: How Fast Does the Man Fall?
      If a 180 lb. man drops 1150 feet from a building, how many km per hour
      will he be going when he hits the ground?

A:
     In these physics problems, the weight of the man is unimportant.  The
     problem can be solved without knowing his weight.  The formula used
     is:

    2        2
(vf)  =  (v0)   +  2*a*(delta y)

where:

vf is the velocity of the object when it hits the ground
     (or final velocity)
vo is the object's original velocity
a is the acceleration due to gravity
delta y is how far it falls

  2       2
vf  =  (0)  + 2*(32 ft/sec^2)*(1150 ft)

  2
vf  =   73600 ft^2 / sec^2

now take the square root of vf^2 to get vf...

vf = 271.29 ft/sec

   271.29 ft/sec X  .6818182 = 184.97 MPH